SAT math - Number and Operations

SAT math - Number and Operations

How can we find the result of the following expression:

(2-(3-(1-(2-(4-3)))))-(2-(3-(1-(2-(4+3)))))

Answer
http://www.satmath4u.com/threads/33-SAT-Operations-inside-parentheses

You have to work from the innermost to the outermost parentheses 

(2-(3-(1-(2-(4-3)))))=(2-(3-(1-(2-(-1)))))=(2-(3-(1-(2+1))))=(2-(3-(1-3)))=(2-(3-(-2)))=(2-(3+2))=(2-5)=-3

and the rightmost expression is 

(2-(3-(1-(2-(4+3)))))=(2-(3-(1-(2-(7)))))=(2-(3-(1-(-5))))=(2-(3-(1+5)))=(2-(3-(6)))=(2-(-3))=(2+3)=5

So the final result is (-3)-5=-8